Question

10. sec? A + cosec2 A = sec? A. cosec? A​

Answer 1

Answer:

$\sec^{2} a + \cosec^{2} a \\ = \frac{1}{ { \cos}^{2} \alpha } + \frac{1}{ { \sin}^{2}a } \\ = \frac{ { \sin }^{2}a + { \cos }^{2}a }{ {sin }^{2}a \times { \cos }^{2}a} \\ = \frac{1}{ {sin }^{2}a \times { \cos }^{2}a}\\ = { \sec }^{2} a .\: cosec ^{2} a$