Math, asked by aarav8597, 1 year ago

10. Shanker takes a loan of 10,000 at a compound
interest rate of 10% per annum (p.a.)
(1) Find the compound interest after one year.
() Find the compound interest for 2 years
() Find the sum of money required to clear the
debt at the end of 2 years.
(iv) Find the difference between the compound
interest and the simple interest at the same
rate for 2 years.
11. Find the compound interest on 5000 at
12% pa for 1 year, compounded half-yearly.
12. Find the amount and the compound interest on
16000 for years at 10% p.a., the interest
being compounded half-yearly.
13. Calculate the amount due and the compound
interest on 40000 for 2 years when the rate
of interest successive years is 7% and 8%
respectively
14. If the simple interest on a sum of money for
2 years at 5% per annum is 50, what will be the
compound interest on the same sum at the same
rate for the same time
[Hint. First find P by using
1100* > so-Px2x5
100

Answers

Answered by gopalsibapaul01
2

Answer:

1

Secondary SchoolMath 5 points

Shankar takes a loan of rupees 10000 at a compound interest rate of 10% per annum.1) find the compound interest after one year.2) find the compound interest for 2 years3) find the sum of money requried to clean the debt at the end of 2 years.

Ask for details Follow Report by Kishan013 10.09.2017

Answers

siddhartharao77

siddhartharao77 Genius

1. Compound interest after one year = 10000 * 10/100

= 1000

2. Compound interest for 2 years = 11000 * 10/100

= 1100

3. Sum of money required to clean the debt = 11000 + 1100

= 12100 rs

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