Question

10.Show that the total energy of the stretched spring remains conserved when it is released.
Find expression for the maximum speed.शोध द टोटल एनर्जी ऑफ ​

Answer 1

Answer:

Spring force =−kx

Δ (work done) =F.dx

Total work done =∫F.dx

∫(−kx)dx

∫x2x1−kxdx

w=21kx12−21kx22

Work done =change in kinetic energy

=21mv22−21mv12

21mv22−21mv12=21kx12−21kx22

21mv2+21kx2=C

Maximum velocity =

Answer 2

Answer:

If we stretch a spring to a distance Xm, it's P. E. is 1/2kX²m. When it is released, it begins to move under the spring force till it reaches the equilibrium position X=0, where it has maximum velocity. All the P. E. is converted into K. E. Due to inertia of motion, the body overshoots the X=0 position.