Question

10.
sin 1350 cos 120°
sin 135° + cos 120°
= 3+22.​

Answer 1

Step-by-step explanation:

{sin(135)−cos(120)}/{sin(135)+cos(120)} ——————— (1)

sin(135) = 1/√2,

cos(120) = -1/2,

Substituting these values in equation (1),

{(1/√2) - (-1/2)}/{(1/√2) + (-1/2)}

= (1/√2 + 1/2)/(1/√2 - 1/2)

= (√2 + 1)/(√2 - 1)

On rationalizing, i.e., multiplying and dividing by (√2 - 1), we get

= (√2 +1)*(√2 + 1)/(√2 - 1)*(√2 +1)

=(√2 + 1)^2/2–1

=(√2^2 + 2√2*1 + 1^2)/1

= 2 + 2√2 + 1

= 3 + 2√2

Hope it helps!

Thanks :)

Answer 2

Answer:

this question is not correct