10.six bags of marble conlain 18,19,21 23,25 and 34 marbles respectively all the marbles in one of the bags are chipped.the other bags contain no chipped marbles.ria takes three of the bags and ruhi takes two of the others pre of the bags of chipped maroles remains.if ria geta twice aS many marbles as ruhi how many chipped marbles are there?
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Answer:
23 chipped Marbles
Explanation:
ria gets 34 + 25 + 19 = 78
Ruhi gets 18 + 21 = 39
78 = 39 * 2
remaining bag 23
23 chipped marbles are there
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Way to solve
total marbles = 18 + 19 + 21 + 23 + 25 + 34 = 140
ria gets twice of ruhi
Let say ruhi gets = X
then ria gets = 2X
Let say chipped marbles = y
X + 2X + Y = 140
=> 3X + Y = 140
=> 3X + Y = 3 * 46 + 2
=> Y = 3 (46 - X) + 2
=> Y = 3 n + 2
only 23 ( 3* 7 + 2) satisfies this condition
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