10) Six diesel engines consume 900 liters of diesel, when each one is running for 5 hrs a day. How much diesel will be required by 9 engines, each running 8 hrs a day when 5 diesel engines of former type consume as much diesel as 8 diesel engines of the latter type?
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first let us find how many liters will 5-eng of type-1 consume when working for 5 hours
for 6-eng(type-1) -> 900 liters
then for 5-eng(type-1) -> x liters?
therefore x = (900*5)/6 = 750 liters
NOW .. it is clearly given that 8-eng(type2) consume same diesel as 5-eng(type1)
for 5 hours ...
therefore for 8-eng(type2) -> 750 liters
then for 9-eng(type-2)-> x liters ?
=> x = (750*9)/8 = 843.75 liters for 5 hours
when 9-eng of type-2 consume 843.75 liters for 5 hours then for 9 hours how much do they consume ?
for 5 hours -> 843.75 liters
for 9 hours -> x hours ?
therefore x = (843.75*9)/5 = 1518.75 liters (ANSWER)
for 6-eng(type-1) -> 900 liters
then for 5-eng(type-1) -> x liters?
therefore x = (900*5)/6 = 750 liters
NOW .. it is clearly given that 8-eng(type2) consume same diesel as 5-eng(type1)
for 5 hours ...
therefore for 8-eng(type2) -> 750 liters
then for 9-eng(type-2)-> x liters ?
=> x = (750*9)/8 = 843.75 liters for 5 hours
when 9-eng of type-2 consume 843.75 liters for 5 hours then for 9 hours how much do they consume ?
for 5 hours -> 843.75 liters
for 9 hours -> x hours ?
therefore x = (843.75*9)/5 = 1518.75 liters (ANSWER)
Answered by
1
Answer:
1518.75
Step-by-step explanation:
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