Question

10.Solve for b: 5(b-1)+2(b+3)+6=0

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Answer 1

Answer :-

• The required number is -1.

Step-by-step explanation:

To Find :-

• Solve for b

Solution:

Given equation :-

• 5(b-1)+2(b+3)+6=0

By simplifying the equation :-

⇒ 5 ( b - 1 ) + 2 ( b + 3 ) + 6 = 0

⇒ (5)(b) + (5)(-1) + 2 ( b + 3 ) + 6 = 0

⇒ 5b + (5)(-1) + 2 ( b + 3 ) + 6 = 0

⇒ 5b - 5 + 2 ( b + 3 ) + 6 = 0

⇒ 5b - 5 + (2)(b) + (2)(3) + 6 = 0

⇒ 5b - 5 + 2b + (2)(3) + 6 = 0

⇒ 5b - 5 + 2b + 6 + 6 = 0

⇒ 5b + 2b - 5 + 6 + 6 = 0

⇒ 7b - 5 + 12 = 0

⇒ 7b + 7 = 0

⇒ 7b = - 7 + 0

⇒ 7b = - 7

⇒ b = -7/7

⇒ b = -1

Hence, The required number is -1.

Answer 2

Question:

Solve for b :

• 5(b-1)+2(b+3)+6=0

Solution:

Substituting this given equation,

5(b-1)+2(b+3)+6=0

➞ 5b - 5 + 2 ( b + 3 ) + 6 = 0

➞ 5b - 5 + 2b + 6 + 6 = 0

➞ 5b + 2b + 6 + 6 - 5 = 0

➞ 7b + 6 + 6 - 5 = 0

➞ 7b + 12 - 5 = 0

➞ 7b + 7 = 0

➞ 7b = - 7 + 0

➞ 7b = -7

➞ b = -7/7

➞ b = -1

Hence, the required Value of b is -1

Happy Learning!!