Question

10 Solve the following quadratic equation.
$4 \sqrt{6 {x }^{2} } - 13x - 2 \sqrt{6}$
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Answer 1

$4 \sqrt{6} {x}^{2} - 13x - 2 \sqrt{6} = 0 \\ \\ 4 \sqrt{6} {x}^{2} - 16x + 3x - 2 \sqrt{6} = 0 \\ \\ 4x( \sqrt{6} x - 4) + \sqrt{ \frac{2}{3} } ( \sqrt{6} x - 4) = 0 \\ \\ (4x + \sqrt{ \frac{2}{3} } )( \sqrt{6} x - 4) = 0 \\ \\ x = \frac{4}{ \sqrt{6} } ........x = \frac{1}{2 \sqrt{6} }$

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Answer 2

Answer:

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