Question

10. Solve x^2+3x+5=0​

Answer 1

it can be solved with dharacharya method

Answer 2

$\huge\boxed{ \fcolorbox{black}{pink}{❥Answer:}}$

 y=ax2+bx+c and the formula

x=−b+√b2−4ac2a orx=−b−√b2−4ac2a

then if y=x2+3x−5

a =1, b = 3 and c = -5

x=−3+√32−(−20)2 orx=−3−√32−(−20)2