10 std
chapter no 1
liner equation in two veriable
x+7y=10
3x-2y=7
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x+7y=10; ------------(I)
3x−2y=7 -----------(II)
multiplying (I) with 3
3x+21y=30; ---------(III)
3x−2y=7 ---------------(IV)
Subtracting (IV) from (III) we get
3x+21y−3x+2y=30−7
23y=23
⇒1
Putting the value of y in (IV) we get
3x−2(1)=7
⇒3x=7+2=9
⇒3x=9
⇒x=3
Thus, (x,y)=(3,1)
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