Question

10 std solve the equations by factorism​

Answer 1

Answer:

2y^2 + 26y + y + 13 = 0

2y ( y + 13 ) + 1 ( y + 13 ) = 0

( y + 13 ) ( 2y + 1 ) = 0

Answer 2

Answer:

2y^2+27y+13=0

=> 2y^2+26y+y+13=0

=> 2y(y+13)+1(y+13)=0

=> (y+13)(2y+1)=0

so, y+13=0

=> y= -13

2y+1=0

=> 2y= -1

=> y= -1/2