Question

10 students can do a job in 8 days ,but on the starting day ,2 of them in formed that they are not coming.by what fraction the no.of days required for whole work will increase

Answer 1

Work Done by 10 people every day= (1/8)×Work
Work done by 1 person every day=(1/80)×Work

So if 8 people decide to work, work done by them daily= (8/80)×work or (1/10)×work

Then no of days taken is
Work÷(1/10×work)= 10 days

Therefore Increase= With 10 people- with 8 people = 2 days.

The increase in no of days =2

Answer 2

Answer:

2 days

Step-by-step explanation:

Given: 10 students can do a job in 8 days

To Find: In how many extra days 8 students can do the same work

Solution:

If 10 student can do a work in 8 days the,

Work done by the 10 students everyday = $\frac{1}{8}$ work done

Work done by the 1 student everyday = $\frac{1}{80}$ work done

∴ Work done by the 8 student everyday = $(\frac{1}{80} * 8) = \frac{1}{10}$ work done

Then, No. of days to complete the work by 8 student = $\frac{1}{1/10}$  = 10 days

∴ 8 students will take 10 days to complete the work which is 2 days more if 10 students worked

#SPJ2