Question

10 sum of the integer​

Answer 1

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Lets, consider 1 to 10 an AP (Arithmetic Progression)

Here, 1st number i.e, a = 1

Common Difference i.e, d = 1

Common Difference i.e, d = 1Total numbers in the series i.e, n= 10

Common Difference i.e, d = 1Total numbers in the series i.e, n= 10According to the Sum of AP,

• Common Difference i.e, d = 1Total numbers in the series i.e, n= 10According to the Sum of AP,S = (n/2)(2*a + (n-1)*d)

• Common Difference i.e, d = 1Total numbers in the series i.e, n= 10According to the Sum of AP,S = (n/2)(2*a + (n-1)*d)S = (10/2)(2*1 + (10 - 1)* 1)

• Common Difference i.e, d = 1Total numbers in the series i.e, n= 10According to the Sum of AP,S = (n/2)(2*a + (n-1)*d)S = (10/2)(2*1 + (10 - 1)* 1)S = (10/2)(2 + 9)

• Common Difference i.e, d = 1Total numbers in the series i.e, n= 10According to the Sum of AP,S = (n/2)(2*a + (n-1)*d)S = (10/2)(2*1 + (10 - 1)* 1)S = (10/2)(2 + 9)S = (5)(11)

S = 55

S = 55S = 55

S = 55S = 55Therefore, Sum of required sequence from 1 to 10 is 55.