Math, asked by krushna5395, 11 months ago

10. Sum of the odd numbers from 1 to 2019 both inclusive, is divisible by
A) only 100
B) only 101
C) both 100 and 101
D) neither by 100 nor by 101​

Answers

Answered by MaheswariS
6

Answer:

option (c) is correct

Step-by-step explanation:

Sum of the odd numbers from 1 to 2019 both inclusive, is divisible by

A) only 100

B) only 101

C) both 100 and 101

D) neither by 100 nor by 101​

Clearly, the numbers 1,3,5,...............2019

form an A.P with common difference 2.

Here,

First term, a=1

Last term, l=2019

\text{Number of terms },n=\frac{l-a}{d}+1

\implies\:n=\frac{2019-1}{2}+1

\implies\:n=\frac{2018}{2}+1

\implies\:n=1009+1

\implies\:n=1010

\text{Sum of the A.P },S_n=\frac{n}{2}[a+l]

\implies\:S_n=\frac{1010}{2}[1+2019]

\implies\:S_n=\frac{1010}{2}[2020]

\implies\:S_n=(1010)(1010)

\implies\:S_n=101\times\:101\times\:100\:\text{which is divisible by both 100 and 101}

Answered by ItsBrainlyStarQueen
0

Answer:

C) both 100 and 101

Step-by-step explanation:

10. Sum of the odd numbers from 1 to 2019 both inclusive, is divisible by

A) only 100

B) only 101

C) both 100 and 101 ✓

D) neither by 100 nor by 101

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