Question

10.
tan³x+tan²x+tanx+1
sec²xdx/
√tan²x+2tanx+3
Hint. Put tan x=t.​

Answer 1

Step-by-step explanation:

I=∫

tanx

(1+tan

2

x)dx

I=∫

tanx

sec

2

x dx

Put tanx=t

sec

2

x dx=dt

Thus, I=∫

t

dt

I=

3/2

t

3/2

+C

I=

3

2

(tanx)

3/2

+C