10 term of an ap is 47 and its first term is2 find the sum of its first 15 terms
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555
Step-by-step explanation:
It is in A.P . a+9d=47 & a=2 then d=5 sum of n terms in A.P equal to
n/2(2a+(n-1)d) then sum of 15 terms equal to 15/2(2*2+14*5)=15/2(4+70)=
15/2(74)=555
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