10 th sum please ....
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As AB || DE
angle BAE = angle DEA (alternate interior angles)
now angle CDE = 53
anglen DEA= 35
so by applying angle sum property we know
DEC + CDE + DCE = 180°
so DCE = 180 - (35+53)
Angle DCE = 92
angle BAE = angle DEA (alternate interior angles)
now angle CDE = 53
anglen DEA= 35
so by applying angle sum property we know
DEC + CDE + DCE = 180°
so DCE = 180 - (35+53)
Angle DCE = 92
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