10. The 8th term and 13th term of the series
-1/32,-1/16, -1/8,....are
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Answer:
Step-by-step explanation:
a=-1/32
d=a2-a1=-1/16-(-1/32)
d=-1/16+1/32
d=-1/32
a8=a+7d
a8= -1/32+7(-1/32)
a8= -1/32-7/32
a8= -8/32
a8= -1/4
a13=a+12d
a13= -1/32+12(-1/32)
a13= -1/32-12/32
a13= -13/32
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