Math, asked by vardhanivijaya012, 2 months ago

10. The 8th term and 13th term of the series
-1/32,-1/16, -1/8,....are​

Answers

Answered by deep101171
2

Answer:

Step-by-step explanation:

a=-1/32

d=a2-a1=-1/16-(-1/32)

d=-1/16+1/32

d=-1/32

a8=a+7d

a8= -1/32+7(-1/32)

a8= -1/32-7/32

a8= -8/32

a8= -1/4

a13=a+12d

a13= -1/32+12(-1/32)

a13= -1/32-12/32

a13= -13/32

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