Question

10. The area of a square is 100 sq m. Its perimeter is
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Answer 1

Answer:

Explanation:

Area of square = a*a

Area of square =a square

100=a square

Now taking the underroot on both side

10= a

Perimeter of square = 4*a

Perimeter of square =4*10

Perimeter of square =40m

Answer 2

Given:

• The area of a square is 100 sq m.

To Find:

• it's perimeter.?

Solution:

➢ here we have the area of the square and we should find its perimeter so, firstly we should find its side.!

${ : \implies} \sf \: area \: of \: a \: square = side \times side \\ \\ \\ { : \implies} \sf \: area \: of \: a \: square = {s}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ { : \implies} \sf \: {100cm}^{2} = {s}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ { : \implies} \sf \: s = \sqrt{100} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ { : \implies} \sf { \underline {\boxed{ \pink{ \sf side = 10cm }}}}\bigstar\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

✬Now let's find the perimeter of the square ✬

$: \longrightarrow \sf \: perimeter \: of \: a \: square = 4 \times side \\ \\ : \longrightarrow \sf \: perimeter \: of \: a \: square = 4 \times 10 \: \\ \\ : \longrightarrow \sf \: perimeter \: of \: a \: square = 40cm \bigstar$

$\rm\therefore {\underline{ \purple{ perimeter \: of \: the \: square = 10cm}}}$

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Knowledge sphere:

$\leadsto \sf \: area \: of \: a \: rectangle = l \times b \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \leadsto \sf \: area \: of \: a \: rhombus = \frac{ d_{1} \times d_{2} }{2}\: \: \: \: \: \: \: \: \: \\ \\\leadsto \sf \: area \: of \: a \: circle =\pi {r}^{2}\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \leadsto \sf \: area \: of \: a \: triangle = \frac{1}{2} bh\: \: \: \: \: \: \: \: \:\: \: \: \: \: \: \: \: \: \: \: \: \:$