Question

10. The area of a triangle with vertices (3, 0), (7, 0) and (8, 4) is ...​

Answer 1

Step-by-step explanation:

The area of the triangle = 1/2 {3 (0-4)+7 (4-0)+8 (0-0)} = 1/2 {-12+28+0} = 8 square units

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Answer 2

Answer:

8 unit^2

(3,0) (7,0) (8,4)

$\frac{1}{2} (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2))$

$\frac{1}{2} (3 (0 - 4) + 7(4 - 0) + 8(0 - 0) \\ = \frac{1}{2} (3 \times - 4) + (7 \times 4) + (8 \times 0) \\ = \frac{1}{2} ( - 12) + (28) + 0 \\ = \frac{1}{2} ( 16) \\ = 8$

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