10. The area of trapezium of height 10 cm is
175 sq. cm. If one of the parallel sides measures
20 cm, find the length of the other parallel side.
Answers
Answered by
7
AnSwer -:
The other parallel sides -: 15 cm
__________________________________________________________
Explanation-:
Formula of area of trapezium-:
“A = 1/2 x h (a+b)”
A = Area
H = height
(A +b) = sum of parallel sides
____________________________
Given ,
Area of trapezium-: 175 cm^2
Height of trapezium = 10 cm
One parallel side of trapezium = 20 cm
To find ,
Other parallel side of trapezium
_______________________________
Let the other parallel side of trapezium
be y.
Formula of area of trapezium-:
“A = 1/2 x h (a+b)”
A = Area =175 cm^2
H = height= 10 cm
(A +b) = sum of parallel sides = (20 + y )
Then ,
1/2 x 10 (20 + y) = 175 cm^2
= 5 x (20 + y) = 175 cm^2
= 20 + y = 175/5
= 20 + y = 35
= y = 35 - 20
= y = 15
Therefore
The other parallel sides -: 15 cm
_____________________________
Verification-:
Formula of area of trapezium-:
“A = 1/2 x h (a+b)”
A = Area =175 cm^2
H = height= 10 cm
(A +b) = sum of parallel sides = (20 + 15)
Then ,
= 1/2 x 10 (20 +15) = 175 cm^2
= 5 (20 +15 ) = 175 cm^2
= 5 x 35 = 175 cm^2
= 175 cm^2 = 175 cm^2
Therefore,
LHS = RHS
Hence verified
____________________________
Trapezium-: A trapezium is a type of
quadrilateral, which has only two
parallel sides and the other two sides
are non-parallel.
_____________________________
The other parallel sides -: 15 cm
__________________________________________________________
Explanation-:
Formula of area of trapezium-:
“A = 1/2 x h (a+b)”
A = Area
H = height
(A +b) = sum of parallel sides
____________________________
Given ,
Area of trapezium-: 175 cm^2
Height of trapezium = 10 cm
One parallel side of trapezium = 20 cm
To find ,
Other parallel side of trapezium
_______________________________
Let the other parallel side of trapezium
be y.
Formula of area of trapezium-:
“A = 1/2 x h (a+b)”
A = Area =175 cm^2
H = height= 10 cm
(A +b) = sum of parallel sides = (20 + y )
Then ,
1/2 x 10 (20 + y) = 175 cm^2
= 5 x (20 + y) = 175 cm^2
= 20 + y = 175/5
= 20 + y = 35
= y = 35 - 20
= y = 15
Therefore
The other parallel sides -: 15 cm
_____________________________
Verification-:
Formula of area of trapezium-:
“A = 1/2 x h (a+b)”
A = Area =175 cm^2
H = height= 10 cm
(A +b) = sum of parallel sides = (20 + 15)
Then ,
= 1/2 x 10 (20 +15) = 175 cm^2
= 5 (20 +15 ) = 175 cm^2
= 5 x 35 = 175 cm^2
= 175 cm^2 = 175 cm^2
Therefore,
LHS = RHS
Hence verified
____________________________
Trapezium-: A trapezium is a type of
quadrilateral, which has only two
parallel sides and the other two sides
are non-parallel.
_____________________________
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