Question

10. The average of the ages of a man and his daughter
is 34 years. If the respective ratio of their ages four
years from now is 14:5, what is daughter's present
age?​

Answer 1

Answer:

16

Step-by-step explanation:

Let the man's age be x and daughter's age be y

So (x+y)/2 = 34

x+y = 68 -----------(1)

Father's Age after four years = x+4

Daughter's age after four years = y+4

(x+4)(y+4) = 14/5

5(x+4) = 14(y+4)

5x+20 = 14y + 56

5x-14y = 36 --------(2)

(1) * 5

5x + 5y = 340 --------(3)

(3) - (2)

-19y = -304

y = 16

So daughter's present age = 16