Question

10. The bisector of interior ∠A of ΔABC meets BC in D and bisector of external ∠A
meets BC (produced) in E. Prove that BD/BE=CD/CE.
.

Answer 1

Answer:

this pic will help you

Step-by-step explanation:

thank my 5 answers please

glad to help you stay safe stay blessed have a nice day

Answer 2

Answer:

hope u understand this if not able to u can ask which part is not clear

To prove: BD/BE = CD/CE

Proof: In △ABC, AD bisects interior ∠A

∴ AB/AC = BD/DC (Angle bisector theorem) ..........1)

Similarly in △ABC, AE bisects exterior ∠A

∴ AB/AC BE/CE ...........2)

From equation (1) and (2)

AB/AC = BD/DC = BE/CE = CD/CE

Hence proved.