Question

10. The brakes applied to a car produces a negative acceleration of 10 ms. If car takes 5
second to stop after applying the brakes, calculate the distance covered by the car before
coming to rest.​

Answer 1

acceleration = -10m/s^2

time = 5sec

car has to come to rest so its final velocity is 0

v = u +at

0 = u + (-10*5)

0 = u -50

u=50

distance = 1/2at^2 + ut

distance = 1/2(10)(25) + (50)(5)

375m