Question

10. The circle sides made inside the ABC touch BC, CA and AB at D, E and F, respectively. If AB = AC, then prove that BD is = CD.​

Answer 1

AF = AE ( tangents from the same external point)

similarly,

FB = BD.... (i)

EC = DC... (ii)

given that AB = AC

AF + FB = AE + EC

FB = EC

BD = DC (from i and ii )

Hence proved.

Answer 2

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