10. The Coulomb's
repulsive force between two
point charges placed at distance d apart, is F. If
the distance is increased to 2d then the
repulsive force between the charges, as
compared to its previous value, will become
(A)1/4 (B)1/2 (C)3/4 (D)Same
Answers
Answered by
2
Answer:
Sima and Raina
Explanation:
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Answered by
8
Answer:
a)1/4
because force is inversely proportional to the square of force.
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