Question

10. The figure below show a velocity- time graph for a scooterist having a total mass of 150
kg. From the graph calculate a)The acceleration in first 4 seconds b) The distance
covered in first 4 seconds c) The force acting in the first 4 seconds​

Answer 1

Given:

The figure below show a velocity- time graph for a scooterist having a total mass of 150 kg.  

To find:

From the graph calculate  

a)The acceleration in first 4 seconds  

b) The distance covered in first 4 seconds  

c) The force acting in the first 4 seconds​

Solution:

Consider the given graph while going through the following steps.

a) The acceleration in the first 4 seconds = the slope of the graph AB.  

AB = BF/AF =20-0/4 = 5 m/s2  

b) The distance covered in the first 4 seconds = area of Δ ABF  

=  1/2 bh  

= 1/2  AF × BF

= 1/2 × 4 × 20  

= 40m  

c) Force acting on the body in the first four seconds = ma  

= 150 × 5  

= 750 N

Therefore, we have, a) 5 m/s2 b) 40m c) 750 N

Answer 2

Answer:

The answers are: 5m/s^2    80m   450N

Explanation:

We know that the total mass is 150kg

m=150kg

as per the graph we can decipher that velocity acheived in 4secs is 20m/s

v=20m/s

t=4 secs

u=0m/s (the scooter was initially at rest)

we also know that acceleration is (v-u)/t

Therefore accleration is 20-0/4

a=5m/s^2

we know that

distance=speedxtime

speed(velocity)x time= 20x4 = 80m

Force= mass x accleration

F=150x5

=450N