10. The force between two objects decreases by 36% when the distance between them is increasedby 4 m. The original distance between them in meter is 1) 4 2) 16 3) 10 4) 12
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Answer:
16cm
Explanation:
Let force between the objects =F
Distance between them =r.
For case II distance, r1=(r+4)
New force, F1=36%, less than F
∴F1=F(1−36100)=64100F
⇒G.m.m(r+4)2=64100G.m.mr2
⇒100r2=64(r+4)2 Take square roots on both sides.
10r=8(r+4)⇒10r=8r+32
⇒(10−8)r=2r=32
r=16cm.
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