Question

10.
The given figure shows a statue. It exerts a pressure of 340 Pa on the floor. What is the weight of the statue if base area of its one foot is 17 cm??
(NS0-2016)
(A) 5.780 N
(B) 1000 N
(C) 1.156 N.
(D) 2000 N​

Answer 1

Answer:

1.156 N

Explanation:

As we Know that Pressure (Pa) =

Force (N)/Area (M^2)

Pressure increase with in increased area as question asking about one foot so pressure will be doubled = 340pa * 2 = 680pa

Now,

Force = Pressure * Area

680pa * (17÷10000) m^2

680pa * 0.0017

= 1.156 N

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Answer 2

Answer:

Option C

Explanation:

Tip

• Pressure is defined as the physical force exerted on an object. The force applied is perpendicular to the surface of objects per unit area. The basic formula for pressure is F/A (Force per unit area). Unit of pressure is Pascals (Pa).

Given

pressure of 340 Pa

area of its one foot is 17 cm

Find

Right Option

Solution

As we Know that Pressure (Pa) =

$Force (N)/Area (M^2)$

Pressure increase with in increased area as question asking about one foot so pressure will be doubled$= 340pa * 2 = 680pa$

Now,

$Force = Pressure * Area$

$680pa * (17/10000) m^2$

$680pa * 0.0017$

$= 1.156 N$

Final Answer

Option C is right

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