Question

10. The HCF and the product of two numbers are 8 and 9600 respectively. How many pairs of numbers exist which satisfy the given conditions? (1) 3 (2) 4 (3) 6 (4) 10​

Answer 1

Answer:

it will be 6 as

Step-by-step explanation:

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Answer 2

Answer:

answer is 10

Step-by-step explanation:

hcf is 8 hence both number r divisible by 8

hence (8x)(8y)=9600

xy=9600/64 =1200

now do factors of 1200 they r more then 6 hence possible paire is 10