Question

10) The LCM of two numbers is 280 and GCD is 14. One of the numbers is less than 50 and the other is greater than
50. Find the two numbers.​

Answer 1

GIVEN: HCF+LCM= 600, ONE NUMBER= 280

Let the HCF= X

LCM= 14X

HCF+LCM= 600

X+ 14X=600

15X= 600

X= 600/15

X= 40

HCF= 40

LCM = 14X= 14× 40= 560

HCF×LCM= 1ST NUMBER × 2ND NUMBER

40× 560= 280× 2ND NUMBER

2ND NUMBER= (40×560) /280

2ND NUMBER= 40×2

2ND NUMBER= 80

Hope this will help you....