(10) The legs of a right triangle are in the ratio 3 : 4 and its area is 1014 cm. Find the lengths of its sides and its perimeter.
Answers
Step-by-step explanation:
Let it's leg be 3x and 4x. Then,
according to question,
Area of right angle triangle = 1/2 × 3x × 4x
1,014 = 6x^2
1,014/6 = x^2
√169 = x
13 cm = x
Hence, first side = 3×13 = 39 cm
second side = 4×13 = 52 cm.
We know that
H^2 = P^2 + B^2
H^2 = 39^2 + 52^2
H^2 = 1521 + 2704
H = √4225
H = 65 cm.
Hence, the hypotenuse is 65 cm.
Perimeter of triangle = sum of all side
so,
perimeter = 39+52+65 cm
perimeter of triangle = 156 cm
Answer:
Step-by-step explanation:
Step-by-step explanation:
Let it's leg be 3x and 4x. Then,
according to question,
Area of right angle triangle = 1/2 × 3x × 4x
1,014 = 6x^2
1,014/6 = x^2
√169 = x
13 cm = x
Hence, first side = 3×13 = 39 cm
second side = 4×13 = 52 cm.
We know that
H^2 = P^2 + B^2
H^2 = 39^2 + 52^2
H^2 = 1521 + 2704
H = √4225
H = 65 cm.
Hence, the hypotenuse is 65 cm.
Perimeter of triangle = sum of all side
so,
perimeter = 39+52+65 cm
perimeter of triangle = 156 cm