Math, asked by sndpchn76, 7 months ago

10. The lengths of the diagonals of a rhombus are 16 cm and 12 cm respectively.
Find the length of each of its sides.
11. In the given figure ABCD is a square. Find the measure of CAD.
Hint. DA - DC LACD = DAC = x (say)
Then, x++90°=180° Find x.​

Answers

Answered by tummakeerthana19
3

10)in rhombus ABCD,

AC and BD meet at o

AC=16cm,AO=16/2=8cm

BD=12cm,BO=12/2=6cm

in triangle, AOB,

angle AOB=90°

AO²+BO²=AB²

8²+6²=64+36=100=AB²

AB=10cm

therefore, AB=BC=CD=AD=10cm

11)In square ABCD,

angle ACD=angle DAC=x

angle ACD+angle DAC+ angle ADC=180°

x+x+90°=180°

2x=180°-90°=90°

x=90°/2=45°

angle CAD=45°

Similar questions