Question

10. The magnitude of displacement and average velocity
of the top of the seconds hand of a clock of dial
radius R = 25 cm during t= 10s.
(c) and no
(c) and go​

Answer 1

Answer:

R equal 25 cm during the equal 10s

Answer 2

Answer:

Step-by-step explanation:

the angle between initial and final point of second  hand is 60 o { 1s = 6 o  then 10 s = 60 o]

WKT  dispacement is straight line distance between initial and final point

hence the triangle  so formed has an angle of 60o . so it is a equilateral triangle

so the displacement = radius= 25 cm = ¼ m

velocity = displacement / time taken = ¼/10 = 1/40 m/s