Question

10
The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure
of smallest of the angles of the parallelogram​

Answer 1

Let two adjacent angles A and B of ∥gm ABCD be 3x and 2x respectively.

Since the adjacent angles of a parallelogram are supplementary.

∠A+∠B=180

⇒3x+2x=180

⇒5x=180

⇒x=36

∠3×36

=108

and, ∠B=2×36

=72

Since the opposite angles are equal in a parallelgram, therefore, ∠C=∠A=108

and ∠D=∠B=72

Hence, ∠A=108

,∠B=72

,∠C=108

and ∠d=72