Question

10. The molarity of solution which contains 40 g urea dissolved in 500 cm3 is​

Answer 1

Answer:1.334 M

Explanation:mark as brainlist

Answer 2

Answer:

The molarity of the given solution calculated is $1.32M$.

Explanation:

Data given,

The mass of urea, m = $40g$

The volume of the solution, V = $500cm^{3}$

Convert $cm^{3}$ in L

• $1cm^{3}= 10^{-3}L$
• $500cm^{3}= 0.5L$

As we know,

• Molarity = $\frac{number of moles}{Volume (L)}$      -------equation (1)

Now, we know that,

• The molar mass of urea, M = $60g/mol$

Firstly, we have to calculate the number of moles (n):

• Number of moles = $\frac{Given mass}{Molar mass}$ = $\frac{40}{60}$ = $0.66mol$

Now, after putting the value of the number of moles and volume in equation (1), we get:

• Molarity = $\frac{0.66}{0.5}$ = $1.32M$

Hence, the molarity calculated is $1.32M$.