10. The number of terms
from 1 to 200 divisible by 11
are
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Answer:
10th
Maths
Arithmetic Progressions
Introduction to Arithmetic Progressions
How many natural numbers be...
MATHS
How many natural numbers between 200 and 400 are there which are divisible by
i Both 4 and 5?
ii 4 or 5 or 8 or 10?
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ANSWER
The term which are divisible by 8 should also be divisible by 4 and the term which divisible by 10 must be divisible by 5.
So we need to find all the numbers between 200 and 400(excluding 200 and 400) which are divisible 4 and 5.
Now
Total number of natural numbers between 200 and 400 divisible by 4 and 5 = Total number of factors of 4 + Total number of factors of 5-Total number of factors of 20
Now
All numbers between 200 and 400 from an AP with common difference 4 and first term 204 and last term = 396
Let total number of terms be n
Thus t
n
=a+(n−1)d
396=204+(n−1)4
(n−1)4=192
n=49
Again numbers divisible by 5 from an AP with common difference 5 and first term as 205 and last term as 395
Thus number of term =(
d
(a
n
−a)
)+1=(
5
(395−205)
)+1=39
Similarly for numbers of terms divisible by 20 are =(
20
(380−220)
)+1=9
Thus total number of factors of 4 and 5 =49+39−9=79
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