Question

10. The perimeter of a rhombus is 100 cm and one of its diagonals is 48 cm. Find the length of the other
diagonal​

Answer 1

Answer:

please mark me as brainliest answer and follow me please.

Answer 2

Step-by-step explanation:

perimeter of rhombus P=2

$2 \sqrt{ {p}^{2} + {q}^{2} }$

p and q are diagonals

given perimeter=100

$2 \sqrt{ {48}^{2} + {q}^{2} } = 100 \\ \sqrt{2304 + {q}^{2} } = 50 \\ squaring \: on \: the \: both \: sides \\ 2304 + {q}^{2} = 2500 \\ {q}^{2} = 2500 - 2304 \\ {q2} = 196 \\ therefore \: q = 14$