10.) The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is ......... units,
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Answer:
First find length of each sides of ∆
Let A( 4 , 0) B(0, 0) and C (0 , 3)
use distance formula,
AB =√(4²+0) =4
BC= √(0+3²) = 3
CA =√(4²+3²) =5
now ,
perimeter of ∆ = 3 + 4 + 5= 12 unit
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