Question

10. The population of a place increased to 54,000 in 2003 at a rateoll
(i) find the population in 2001.
(ii) what would be its population in 2005?​

Answer 1

Population in 2002 at the rate of 5%per annum = 54000 x ( 5 / 100) = 2700 = 54000 - 2700 = 51300. Population in 2001 at the rate of 5%per annum = 51300 x ( 5 / 100) = 2565.

Answer 2

Step-by-step explanation:

Given that population in 2003 = 54000. Population of a place increased at the rate of 5%per annum. Population in 2002 at the rate of 5%per annum = 54000 x ( 5 / 100) = 2700 = 54000 - 2700 = 51300. Population in 2001 at the rate of 5%per annum = 51300 x ( 5 / 100) = 2565. = 51300 - 2565 = 48735. Now population in 2003 = 54000. Population of a place increased at the rate of 5%per annum. Population in 2004 at the rate of 5%per annum = 54000 x ( 5 / 100) = 2700 = 54000 + 2700 = 56700. Population in 2005 at the rate of 5%per annum = 56700 x ( 5 / 100) = 2835 = 56700 + 2835 = 59,535.