Math, asked by shreyasdeshpande424, 10 months ago

10.
The price of pure coconut oil is 200 per litre. A shopkeeper adulterates it
with some other types of oil at 100 per litre. He sells the mixture at the
rate of * 192 per litre so that to gain 40 % on whole transaction. The ratio
in which he mixed the two oil is:
(A) 1:2
(B) 3:2
(C) 2:4
(D) 1:4
(E) None of these​

Answers

Answered by amitnrw
1

none of these , as 13: 22 is ratio in which he mixed the two oil

Step-by-step explanation:

The price of pure coconut oil is 200 per litre

A shopkeeper adulterates it with some other types of oil at 100 per litre

Let say Ratio mixed in A : B

Cost Price = 200A + 100B  Rs

Total Mixture = A + B  litre

Selling Price = 192(A + B)  Rs

Gain = 192(A + B) - (200A + 100B)

= 92B - 8A  Rs

Gain % = 40 %

Gain = (40/100) * (200A + 100B)

= 80A + 40B

92B - 8A = 80A + 40B

=> 52B = 88A

=> A /B = 52 /88

=> A / B = 13/22

=> A :B = 13 : 22

Hence none of these

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Answered by Itzgoldenking
0

Answer:

none of these , as 13: 22 is ratio in which he mixed the two oil

Step-by-step explanation:

The price of pure coconut oil is 200 per litre

A shopkeeper adulterates it with some other types of oil at 100 per litre

Let say Ratio mixed in A : B

Cost Price = 200A + 100B  Rs

Total Mixture = A + B  litre

Selling Price = 192(A + B)  Rs

Gain = 192(A + B) - (200A + 100B)

= 92B - 8A  Rs

Gain % = 40 %

Gain = (40/100) * (200A + 100B)

= 80A + 40B

92B - 8A = 80A + 40B

=> 52B = 88A

=> A /B = 52 /88

=> A / B = 13/22

=> A :B = 13 : 22

Hence none of these

Step-by-step explanation:

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