10. The probability of change of marks is more: (a) in current audit (b) final audit (c) in interim audit (d) none of the above
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Answer:
Let S be the sample space of tossing a coin
S={H,T}
Probability of getting head =
no. of total outcomes
no. of favorable outcomes
=
2
1
Probability of getting tail =
no. of total outcomes
no. of favorable outcomes
=
2
1
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