*10. The probability that a boy A will get a
scholarship is 0.9 and that another boy B will
bet is 0.8. What is the probability that atleast
one of them will bet the scholarship? (May-2003)
Sal. PCA) - Probability of A
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Answer:Let,
A - Boy gets a scholarship
B - Girl gets a scholarship
so, P(A) = 0.4 & P(B) = 0.5
Prob that alteast one of them gets a scholarship = P (A Union B)
And as we know,
Prob (A Union B) = P(A) + P(B) - P (A intersection B)
Since, boy getting a scholarship and Girl getting a scholarship are independent events we have,
Prob (A Union B) = P(A) + P(B) - [P(A)*P(B)]
Prob (A Union B) = 0.4 + 0.5 - (0.2)
Prob (A Union B) = 0.7
cheers!
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