Question

10) The product of rational number with an irrational number is
Options
Rational number
Whole number
Irrational number
Natural number

Answer 1

Answer:

Irrational Number

Step-by-step explanation:

$let \sqrt{2} \: be \: an \: irrational \: number \:$

$let \: 3 \: be \: a \: rational \: number$

$product \: of \: this \: two \\ 3 \: \times \: \sqrt{2} = \: 3 \sqrt[2]{2} \: \\ which \: is \: a \: irrational \: number$

HOPE IT IS HELPFUL

THAT'S NOT SQUARE ROOT 2 ONLY ROOT 2. ITS MISTAKEN