Question

10. The product of two numbers is 4107. The
LCM of these numbers is 111. Find the HCF
of these numbers.
10​

Answer 1

Answer:

let the number be 37a and 37b .Then,37a × 37 b = 4107 ≥ ab=3. So the required number are (37×1; 37×3) ie (37,111).Therefore, Greater number=111