Question

10.The radius of the base of a cone is 6 cm and its slaint height is 28 cm, then its curved surface is : एक शंकु का वक्रतल ज्ञात कीजिए जिसकी तिर्यक ऊंचाई 28 सेमी तथा आधार की त्रिज्‍या 6 सेमी है -Required to answer. Single choice.

(1 Point)

(a) 528 cm

(b) 528 sq cm

(c) 528 cu cm

(d) None of these

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Answer 1

Answer :

›»› The curved surface area of cone is

Given :

• The radius of the base of a cone is 6 cm and its slaint height is 28 cm.

To Find :

• The curved surface area of cone.

Solution :

To find the curved surface area of cone, we use the formula:-

❰ CSA of cone = πrl ❱

• Radius of cone (r) = 6 cm.
• Slant height of cone (l) = 28 cm.

According to given question,

On putting the given values in the formula, we get

→ CSA of cone = 22/7 * 6 * 28

→ CSA of cone = 22 * 6 * 4

→ CSA of cone = 132 * 4

→ CSA of cone = 528

Hence, the curved surface area of cone is 528 cm².

So, option (c) 528 cm² is correct ✔.

Extra Brainly Knowledge :

• C.S.A of Cone = πrl
• T.S.A of Cone = πr(l + r)
• Volume of Cone = 1/3 πr²h
• Volume of cylinder = πr²h.
• TSA of cylinder = 2πrh + 2πr².
• CSA of cube = 4a².
• TSA of cube = 6a².
• Volume of cube = a³.

Where,

• The value of π is 22/7 or 3.14.
• r is the Radius.
• h is the Height.
• l is the Slant height.
• b is the Breadth.
• a is the Side.

Answer 2

Answer:

$\huge \bf \maltese \: answer \maltese$

$\small \tt \underline {firstly \: lets \: understand \: the \: concept}$

There is cone which has the base as 6 cm and its slanght height as 28 cm. We have tó find its curved surface area .

$\huge \bf \: csa \: of \: cone = \pi rl$

Here,

R = Radius of cone

L = Slanght height of cone

Now,

[Putting values]

$\sf \implies \: csa \: of \: cone \: = \frac{22}{7} \times 6 \times 28$

$\sf \implies \: csa \: of \: cone \: = 22 \times 6 \times 4$

$\sf \implies \: 132 \times 4$

$\sf \implies \: 528 \: cm²$

$\huge \fbox {correct option (c)}$

$\huge \bf \: more \: formula$

$\sf \: volume \: of \: cube \: = {e}^{3}$

$\sf \: volume \: of \: cuboid \: = l \times b \times h$

$\sf \: area \: of \: parallelogram \: = l \times b$

$\sf \: csa \: of \: cone \: = \pi \: rl$

Here,

L = Length

B = Breadth or Base

H = Height

E = Edge

π = 22/7

R = Radius

L (in CSA of cone) = Slanght height