10. The ratio of pure milk to water in a can of
adulterated milk is 8 : 1. If the total quantity of
adulterated milk is 108, find the quantity of
(i) pure milk
(ii) water in it.
Answers
Answered by
2
Answer:
pure milk: 96
water :12
Step-by-step explanation:
8x+x= 108
9x= 108
x =12
so pure milk= 12*8=96
water= 12
Answered by
1
Answer:
hope it will help you it is in simple language
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