Math, asked by Anonymous, 6 months ago

10. The ratio of Reema's age to Sudha's age is 1 : 5. Ten
years later, the ratio of their ages will be 3: 7. Find
their present ages.

Answers

Answered by Anonymous
2

\red{\bigstar} The present ages are

Reema \large\leadsto\boxed{\tt\purple{5 \: years}}

Sudha \large\leadsto\boxed{\tt\purple{25 \: years}}

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• Given:-

Ratio of Reema's age to Sudha's age = 1:5

Ten years later the ratio will be = 3:7

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• To Find:-

Present ages.

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• Solution:-

Let the present age of Reema be 'x' and that of Sudha be 'y'.

• According to the question:-

✯ Ratio of Reema's age to Sudha's age is 1:5.

Hence,

\sf \dfrac{x}{y} = \dfrac{1}{5} \\

\sf x \times 5 = 1 \times y \\

\sf 5x = y \\

\sf y = 5x \dashrightarrow\bf\red{[eqn.i]} \\

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Now,

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✯ Ratio of Reema's age to Sudha's age after 10 years will be 3:7.

Hence,

\sf \dfrac{x + 10}{y +10} = \dfrac{3}{7} \\

\sf 7(x+10) = 3(y+10) \\

\sf 7x + 70 = 3y + 30 \\

\sf 7x + 70 - 30 = 3y \\

\sf 7x + 40 = 3y \\

\sf 7x - 3y = -40\dashrightarrow\bf\red{[eqn.ii]} \\

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• Substituting eqn.[i] in eqn.[ii]:-

\sf 7x - 3y = -40 \\

\sf 7x - 3(5x) = -40 \\

\sf 7x - 15x = -40 \\

\sf - 8x = - 40 \\

\sf x = \dfrac{-40}{-8} \\

\large{\underline{\underline{\rm\pink{x = 5}}}} \\

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• Substituting the value of x in [eqn.i]:-

\sf y = 5x \\

\sf y = 5 \times 5 \\

\large{\underline{\underline{\rm\pink{y = 25}}}} \\

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Therefore, the ages are

Reema = 5 years

Sudha = 25 years

Answered by aayushsharma7956
0

Answer:

THE PRESENT AGE OF REEMA= 5 YEARS

THE PRESENT AGE OF SUDHA = 25 YEARS

Step-by-step explanation:

PARAMETERS GIVEN,

RATIO OF REEMA'S AGE TO SUDHA'S AGE = 1:5

LET THE COMMON RATIO BE x

SO,

AGE OF REEMA = x

AGE OF SUDHA = 5x

AFTER 10 YEARS,

AGE OF REEMA = (x+10)

AGE OF SUDHA = (5x+10)

NOW,

THE RATIO OF AGE OF REEMA TO AGE OF SUDHA=3:7

SO,

A.T.Q.,

(x+10)/(5x+10) = 3/7

7(x+10) = 3(5x+10)

7x+70 = 15x+30

70-30 = 15x-7x

40=8x

x=40/8

x=5

SO,

PRESENT AGE OF REEMA=x=5

PRESENT AGE OF SUDHA = 5x=25

I HOPE YOU UNDERSTOOD THE QUESTION!!!

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