Physics, asked by yuvashreekumaravel18, 8 months ago

10. The relation between time and distance is t = ax^2+bx
where a and Bare constants. The retardation is
(a) 2Bv^3
(b) 2av^3
(c) 2B v3
(d) 2b^2v^3​

Answers

Answered by Sharukh99401
1

ASSALAMUALAIKUM

Explanation:

t=ax

2

+bx

Differentiate w.r.t time

1=2ax

dt

dx

+b

dt

dx

dt

dx

=

2ax+b

1

V=

2ax+b

1

...(1)

a=

dt

dV

=

(2ax+b)

2

−(2a

dt

dx

)

a=

(2ax+b)

2

−2av

....(2)

OK FRND I YOU LIKE PRESS LIKE BUTTON AND FOLLOW FOR MORE SUGGESTIONS

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