Question

10. The roof of a circular room is hemispherical in shape with its inner circumference 35.2 m. Find the
cost of polishing inner surface area of the roof at the rate of 2 per 100 cm2 ?.​

Answer 1

Answer:

hope it will be helpful to you

Answer 2

Step-by-step explanation:

CSA of hemisphereical shell = 2Πr^2

value of 2Πr^2 = 35.2

35.2 = 2Πr^2

35.2 = 2 x 22/7 x r^2

5.6 = r^2

r = 2.36643191324

100 cm ^2 = 2

35.2 m=

1 m = 100 cm

35.2 = 3520 cm

2x3520/100= rs70.4